Gear Speed Calculation

According to known conditions, the shaft deceleration time t=0.25s, the angular acceleration of the output helical gear ɑtooth=ω tooth/t=14.38/0.25=57.52rad/s2, the self-moment of inertia of the output helical gear J gear=(D4×B ×π×ρ)/ 32=(111.4×0.001) 4×31×0.001×3.14×7 700/32=0.003 6kg·m2, where B is the tooth width of the output gear meshing with the rack, in m ; D is the index circle diameter of the output gear meshed with the rack, in m; ρ is the material density, and the steel material density is 7 700kg/m3. Here the gear material is steel, and the output acceleration torque of the helical gear itself loss T tooth = J gear ɑ tooth = 0.003 6 × 57.52 = 0.21N·m. 

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