The self-moment of inertia of the output helical gear J gear=?

The self-moment of inertia of the output helical gear J gear=(D4×B×π×α)/32=(111.4×0.001) 4×31×0.001×3.14×7 700/32=0.003 6kg·m2, converted to the reducer input The load moment of inertia at the end is J load = (J negative + J gear)/i2 = 8.690 57/202 = 0.021 7kg·m2, where J load is the load moment of inertia converted to the input end of the reducer, in kg·m2; 

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